Question

A body is released from the top of a tower of height h metres it takes t seconds to the reach the ground where is the ball at time equals to t by 2

Answer 1

Answer:

3h/4

Explanation:

Refer to the material.

Answer 2

Answer:

h/4

Explanation:

using

s = ut + 1/2.a.t^2

since u = 0

and s=h

we get the relation in terms of time

h = 1/2(-g).t^2

h' = 1/2(-g).(t/2)^2

equate the values of -1/2g.t^2

4h'=h

→h'=h/4

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