Physics, asked by suryaboss5293, 1 year ago

A body is released from the top of a tower of height h meters..After 2 second it isstopped

Answers

Answered by siddhusujhatha

0

Answer:v

f

(after 2s)=g×2=20m/s

s

1

=

2

1

gt

2

s

1

=20m

As it is again released and after 2s it will cover more 20m distance as remaining height=(H−40)m

Explanation:

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