Question

A body is released from the top of a
tower of height h. It takes 't' sec to reach
the ground where will be the ball after time
t/2 sec
​

Answer 1

Answer:

YOUR ANSWER

Explanation:

H=21gt2

At2t,s=21g(t/2)2=41(21gt2)

s=41H

Therefore, the height from ground is given by,

x=H−s=H−41H=43H

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