Physics, asked by veduR77, 1 year ago

A body is released from the top of a tower of height h.It takes time t sec to reach the ground .Where will be the ball after t/2 sec

meenakshi997sa: 4h/5. from the ground...??? or h/5 from the place of dropping

meenakshi997sa: ????

meenakshi997sa: (if g=10m/s2)

veduR77: answer id 3h/4 from ground

meenakshi997sa: ya u r ri8

veduR77: how......but any explanation

veduR77: if it is so please give

meenakshi997sa: ya i already answered it.... :)

meenakshi997sa: have a look plz

Answers

Answered by meenakshi997sa

hope it helps you......

:)...

Attachments:

meenakshi997sa: welcome...... :)..... :D

meenakshi997sa: ya.. sure

meenakshi997sa: here actually h/4 is the height from top ... and i found height from ground at the end....... so h=total height .... h/4 height from top...... hence,..... height from bottom =h-h/4=3h/4

meenakshi997sa: hope i made it clear

meenakshi997sa: ☺...

meenakshi997sa: ☺☺ welcome...☺☺

Previous Question

Next Question