Question

A body is released from the top of a tower of
height H m. After 2 s it is stopped and then
instantaneously released. What will be its height
after next 2s ?
(1) (H-5)m
(2) (H-10)m
(3) (H-20)m
(4) (H-40)m
B C D​

Answer 1

Answer:

(H-40)m

Explanation:

Here is your answer if u get the concept than mark this as a brainliest.

Answer 2

Answer:

option 4 is correct

Explanation:

  v(f)(after 2s)=g*2=20m/s

b1=1/2(gt)^2

b1=20m    

As it is again released and after 2s it will cover more 20m distance as remaining height=(H−40)m