Question

A body is released from the top of the tower fall through the half the height of the tower in 2seconds in what time shall fall through the height of the tower

Answer 1

4 second...

i hope it is right...

plss comment...

Answer 2

s = ut + ½at²

u = 0 , a = 9.8 m/s²

s = 0 + ½ 9.8 2²

or

s = 19.6 m

h = 2s = 39.2 m

Again,

h = 0 + ½at²

39.2 = ½ 9.8 t²

t² = 8

t = 2√2 seconds