Question

A body is released from top of a tower.The velocity of it after t=3 seconds is 6n where n is?

Answer 1

Answer:

• In 2 seconds an object dropped from rest reaches 20 m/s (because g increases velocity by 10 m/s per second). Its average velocity is 10 m/s so it falls 20m in those 2 seconds. Its height will then be (H-40) metres.

Explanation:

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Answer 2

Answer:

From velocity-time relation, (v=u+at)

                  v=gt

                 6n=10×3

                 6n=30

                ∴ n=5