A body is rolling on a horizontal surface.derive an equation for its kinetic energy
Answers
Answered by
6
kinetic energy =1/2*mass *velocity squared
Answered by
1
Explanation:
Total Rolling kinetic energy=Translational K.E+Rotational K.E
=
2
1
MV
2
+
2
1
Iω
2
But ω=
R
V
K.E=
2
1
MV
2
+
2
1
I(
R
V
)
2
=
2
1
MV
2
+
2
1
I(
R
2
V
2
)
For solid sphere I=
5
2
MR
2
K.E=
2
1
MV
2
+
2
1
×
5
2
MR
2
×(
R
2
V
2
)
=
2
1
MV
2
+
5
1
MV
2
=
10
7
MV
2
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