Question

A body is simultaneously given two velocities, one 30 m/s due east and other 40 m/s due north. find the resultant velocity?

Answer 1

Here is your answer
Please mark as brainliest if it would be helpful to you..

Answer 2

Answer:

The resultant velocity along OB will be 50m/s.

Explanation:

Let the body start from O, and follow the path such as OA→AB.

The velocity along the east direction i.e.Va is given as 30 m/s.

The velocity along the north direction i.e.Vb is given as 40 m/s.

According to the parallelogram of the vector OB will give the resultant velocity.

The resultant velocity will be given as,

$R=\sqrt{V^2_a+V^2_b} =\sqrt{30^2+40^2}=\sqrt{900+1600}=\sqrt{2500}=50m/s$

Hence, the resultant velocity along OBwill be 50m/s.