Question

) A body is slidding down a rough inclined plane which makes angle 30° with the
horizontal. The coefficient of the friction between the surfaces of contact of the
body and the plane is 0.25 calculate the acceleration​

Answer 1

Normal=mgcos(30)=√3mg)/2

frictional force=0.25×N= 0.25×√3mg/2

net force on block along the inclined=mgsin(30)-friction

Fnet=mg/2- 0.25×√3mg/2

ma=mg/2- 0.25×√3mg/2

a=g/2 - 0.25×√3g/2