Question

a body is sliding down an incline plane having the coefficient of the friction 0.5 if the normal reaction is twice then the resultant force along inclined plane find the angle between the incline plane in the horizontal ​

Answer 1

Hii Aishwarya,

◆ Answer -

Angle of inclination = 45°

● Explanation -

For a body sliding at inclination α, normal reaction is given as -

N = mg.sinα

Also, resultant force along the inclined plane will be -

R = mg (sinα-μ.cosα)

Given that normal reaction is twice the resultant force.

N = 2R

mg.sinα = 2mg (sinα-μ.cosα)

sinα = 2sinα - 2μ.cosα

sinα = 2 × μ × cosα

tanα = 2 × 0.5

tanα = 1

Taking tan inverse,

α = arctan(1)

α = 45°

Therefore, angle of inclination is 45°.

Thanks dear...