Question

A body is sliding down on inclined plane
have coefficient of friction 0.5. If the
normal reaction is 4 times that of the
resultant downward force along the
incline, find the angle between inclined
plane and the horizontal
(A) 45°
(B) 530
(C) 370
(D) 60°​

Answer 1

Answer:

mgcosθ=2(mgsinθ−μmgcosθ)

⇒cosθ(1+2μ)=2sinθ

⇒tanθ=

2

1+2μ

=

2

1+2×0.5

=1

⇒θ=45 degree.