a body is start to slide over a horizontal surface with an initial velocity of a 0.5ms-1 due to friction,it's velocity decreases at the rate of 0.05ms-2 .how much time will take for the body to stop
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u=0.5m/s
a=-0.05m/s^2 as the body is showing retardation
v=0 as the body will stop
By 1st equation of motion
v=u+at
v-u=at
(v-u)/a=t
Now put the values
(0-0.5)/-0.05
-0.5/-0.05
=10
So ans is 10s
a=-0.05m/s^2 as the body is showing retardation
v=0 as the body will stop
By 1st equation of motion
v=u+at
v-u=at
(v-u)/a=t
Now put the values
(0-0.5)/-0.05
-0.5/-0.05
=10
So ans is 10s
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