Question

A body is taken to a height of (√2 - 1)Re above the Earth surface, where Re is the radius of the Earth. If it is dropped from this height its acceleration will be:
a] 9.8 m/s²
b] 6.5 "
c] 4.9 "
d] 2.5 "​

Answer 1

Answer:

a)$<strong>9.8m</strong><strong>/</strong><strong>{</strong><strong>s</strong><strong>}</strong><strong>^</strong><strong>{</strong><strong>2</strong><strong>}</strong>$

No Matter what is the height,the acceleration at the time free fall will be constant.It is also denoted as g.

HOPE THAT HELPS!!