Physics, asked by mohapatrakanak28, 10 months ago

A body is taken to a height of (√2-1)Re above the earth's surface, where Re is the radius of earth. I f it is dropped from this height, its acceleration will be: ANYTHING OTHER THAN ANS AND ITS PROCESS WILL BE REPORTED.

Answers

Answered by saxenalavi422
4

Answer:

The gravitational potential energy at a height h is

U

h

=

R

e

+h

−GM

e

m

If h=R

e

⇒U

h

=

+2R

e

−GM

e

m

=

2

−mgR

e

& the gravitational potential energy on the surface of earth is

U

s

=

R

e

−GM

e

m

So change in potential energy △U=U

h

−U

s

=

2R

e

−GM

e

m

+

R

e

GM

e

m

=

2R

e

GM

e

m

△U=

2

mgR

e

It means that to move a body of a mass m from the surface of earth to a height h=R

e

, the energy required is

2R

e

GM

e

m

=

2

mgR

e

Explanation:

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