Physics, asked by kripaksheth, 1 month ago

A body is taken to a height of (√2-1)Re above the earth's surface, where Re is the radius of earth. I f it is dropped from this height, its acceleration will be​

Answers

Answered by 10thguruclass
0

Explanation:

Rearranging (Figure), we have

M

E

=

g

R

2

E

G

=

9.80

m/s

2

(

6.37

×

10

6

m

)

2

6.67

×

10

11

N

m

2

/kg

2

=

5.95

×

10

24

kg.

The volume of a sphere is proportional to the radius cubed, so a simple ratio gives us

M

M

M

E

=

R

3

M

R

3

E

M

M

=

(

(

1.7

×

10

6

m

)

3

(

6.37

×

10

6

m

)

3

)

(

5.95

×

10

24

kg

)

=

1.1

×

10

23

kg.

We now use (Figure).

g

M

=

G

M

M

r

2

M

=

(

6.67

×

10

11

N

m

2

/kg

2

)

(

1.1

×

10

23

kg

)

(

1.7

×

10

6

m

)

2

=

2.5

m/s

2

Significance

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