Question

a body is throm with a velocity of 49 m/s at an angle of 30digri above the horizontal calculet maximum height attaned by it (h)​

Answer 1

Answer: 30.625 m

Explanation:

Formula: Max. height achieved during projectile (h) = (u sinΘ)²/ (2g).

By applying the formula in the situation given here-

h = (49 * sin30°)² / (2g)

  = 30.625 m  [As g=9.8].

Answer.