Question

a body is throunw vertically upwards with an initial velocity u reaches a maximum height in 6s the ratio of the distance travelled by the body in the first second to the seventhsecond is

Answer 1

Answer:

Explanation:It is given that, the body reaches the maximum height in 6s. Let u be the initial velocity. At maximum height the velocity is zero. Using the equation of motion as

v=u+at

0=u−(10)(6)

u=60m/s

Distance travelled in nth second is given by:

S  

n

​  

=u+(  

2

a

​  

)(2n−1)

Displacement in 1st second is S  

1

​  

=60−(  

2

10

​  

)(2−1)=55m

Displacement in 7th second is S  

2

​  

=60−(  

2

10

​  

)(14−1)=−5m

So,  

S  

2

​  

 

S  

1

​  

 

​  

=  

5

55

​  

=  

1

11

​  

 

The ratio is 11:1.