Question

a body is throw up with a velocity 50m/s calculate the maximum height reached and the time taken to reach the maximum height ( a= -10m/s^)
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Answer 1

Given:-

→Initial velocity of the body=50m/s

→Acceleration due to gravity= -10m/s²

To find:-

→Maximum height reached by the body

→Time taken to reach maximum height

Solution:-

In this problem:-

•Acceleration due to gravity is given

-10m/s²,as the body is going against gravity

•Final velocity of the body at the highest point is zero,thus while solving this problem,we will take v=0

By using the 3rd equation of motion,we get:-

=>v²-u²=2gh

=>0-(50)²= 2(-10)h

=>-2500 = -20h

=>h = -2500/-20

=>h = 125m

Now,by using 1st equation of motion,we get:-

=>v=u+at

=>0=50+(-10)t

=>-50 = -10t

=>t = -50/-10

=>t = 5s

Thus:-

→Maximum height reached by the

body is 125m.

→Time taken to reach maximum

height is 5s.