Question

A body is thrown at an angle of 30* to the horizontal with the velocity of 30m/s. After 1 sec, it's velocity will be (in m/s) (g = 10m/s)

Answer 1

vx=30cos30=15*3^1/2

vy=30sin30=15

for x direction

vx=u+at

v=15*3^1/2+0*1

v=15*3^1/2

for y direction

v=u-gt

v=15-10*1

vy=5

v resultant=(vx^2+vy^2)^1/2

                 =(225*3+25)^1/2

                  =10*7^1/2

Answer 2

Answer:

vx=30cos30=15*3^1/2

vy=30sin30=15

for x direction

vx=u+at

v=15*3^1/2+0*1

v=15*3^1/2

for y direction

v=u-gt

v=15-10*1

vy=5

v resultant=(vx^2+vy^2)^1/2

                =(225*3+25)^1/2

                 =10*7^1/2

Explanation:

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