Question

A body is thrown at angle 30° to the horizontal with the
velocity of 30 m/s. After I sec, its velocity will be in ml
s) (g= 10 m/s)
(a 105
(b) 700/10
(C) 1007
(d) 140​

Answer 1

Answer:

formula:V=u+at cos theta

Explanation:

v is final velocity

u is intial velocity

a=g

then v=u+at cos theta

v=30+10(1)cos 30

v=30+10*cos √3/2

v=30+8.5

v=38.5mper sec