Physics, asked by RIMSHA7778, 8 months ago

A body is thrown down from a tower of height 192 m with initial velocity 2 m/s find the time taken to hit the groundv velocity just before it hits the ground. the first correct answer will be marked as brainliest❤

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Answered by snehajohnson86
1

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Answered by Darkpit
0
Given : u
y

=0 a
y

=g=9.8m/s
2

Let the projectile's initial velocity be u.
Time of flight T=3 s (given)
Using T=
g
2h



⟹h=
2
gT
2



∴ h=
2
9.8×3
2


=44.1 m

x direction : a
x

=0 ⟹V
x

=u
y direction : V
y

=u
y

+a
y

T
∴ V
y

=0+9.8×3=29.4m/s

Also
V
x


V
y



=tan45
o
=1
⟹ V
x

=V
y

=29.4 m/s
Thus initial speed of the projectile u=V
x

=29.4m/s
solution
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