Question

A body is thrown horizontally from the top of a tower and strikes the ground after 3 seconds at the angle of 45 degree with the horizontal. Find the height of the tower and the speed with which body was thrown.take g=9.8 m/s²

Answer 1

Explanation:

Time = √2H/G

H = 44.1 m

Then Velocity perpendicular To Ground

V = √2gH

V = 30m/s

tan theta = V Predicular/ V parallel

V Parallel = 30m/s.

Theta is 45°