Question

a body is thrown horizontally from the top of a tower.the ball reaches the ground at a horizontal distance s from the tower . then the height of the tower is

Answer 1

Answer:

Given : u

y

=0 a

y

=g=9.8m/s

2

Let the projectile's initial velocity be u.

Time of flight T=3 s (given)

Using T=

g

2h

⟹h=

2

gT

2

∴ h=

2

9.8×3

2

=44.1 m

x direction : a

x

=0 ⟹V

x

=u

y direction : V

y

=u

y

+a

y

T

∴ V

y

=0+9.8×3=29.4m/s

Also

V

x

V

y

=tan45

o

=1

⟹ V

x

=V

y

=29.4 m/s

Thus initial speed of the projectile u=V

x

=29.4m/s

Answer 2

Answer:

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