Question

a body is thrown horizontally from the top of a tower.the ball reaches the ground at a horizontal distance s from the tower . then the height of the tower is

Answer 1

Answer:

Answer :

A

Solution :

As shown in the figure of Example 7.3.

uy=0anday=g=9.8m/s2

sy=uyt+

1

2

 

ayt2

sy=0×3+

1

2

 

×9.8×(3)2

=44.1m

Thus, height of the tower is 44.1m.

Futher, vy=uy+ayt=0+(9.8)(3)=29.4m/s.

As the resultant velocity v makes an angle of 45∘ with the horizontal, so

tan45∘=

vy

vx

 

or1=

29.4

vx

 

vx=29.4m/s

vx=ux+axt

⇒29.4=ux+0

or u_x = 29.4 m//s`

Therefore, the speed with which the body was projected (horizontally) is 29.4 m/s.

Explanation:

Answer 2

Explanation:

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