Question

A body is thrown horizontally with a velocity √2gh from the top of a tower of hight h. It strikes

Answer 1

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Answer 2

Complete Question: A body is thrown horizontally with a velocity √2gh from the top of a tower of height h. It strikes the level of ground through the foot of the tower at a distance x from the tower. Find the value of x.

Answer:

Horizontal Range(x) = 2h

Explanation:

Given:-

           u = Velocity at which the body was thrown

              = √2gh

           h = height of the tower

           x = horizontal range.

Now;-

Since,

           Horizontal Range = Velocity × Time of Flight

Hence,

                         x = √2gh × √2h/g

                         x = √2h × √2h

                         x = 2h

Therefore, the value of x = 2h.

Hope it helps ;-))