Question

A body is thrown up at a speed of 100 m/s. Take g = 10 m/s^2. What is the average velocity as it reaches the ground?

Answer 1

Given : A body is thrown up at a speed of 100 m/s.

Take g = 10 m/s^2.

To Find: the average velocity as it reaches the ground

Solution:

A body is thrown up from the ground

and body reaches back the ground

hence initial and final positions are same

=> Displacement = 0   ( final position - initial position )

Velocity = Displacement / time

Displacement = 0

=> Average velocity = 0/time

=> Average velocity = 0

average velocity as it reaches the ground = 0  m/s

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Answer 2

Given:

A body is thrown up at a speed of 100 m/s. Value of g = 10 m/s².

To find:

Average velocity when the body reaches the ground.

Calculation:

The general expression for average velocity is:

$\rm \therefore \: avg. \: v = \dfrac{total \: displacement}{total \: time}$

Now, DISPLACEMENT is the shortest length between the starting and stopping point of an object.

• In our case, since the body starts from the ground and come back to the ground (the starting and stopping points are the same), THE DISPLACEMENT IS ZERO.

$\rm \implies \: avg. \: v = \dfrac{0}{total \: time}$

$\rm \implies \: avg. \: v = 0 \: m {s}^{ - 1}$

So, average velocity is 0 m/s ,when the body reaches the ground.