Question

A body is thrown up to with a velocity of 40 meters per second. How long does it take to reach the highest point? After how much time will the body come back to the ground? (g = 9.8m/s2)

Answer 1

Answer:

Here, u = 40m/s

V = 0 ( highest point)

A = g = -10m/s²

T = ?

By using,

V = u + at

0 = 40 + -10t

T = 4seconds

Time taken back to ground is

T = 4 +4 = 8seconds

Hope it will help you!!

Answer 2

Here, u = 40m/s

V = 0 ( highest point)

A = g = -10m/s²

T = ?

By using,

V = u + at

0 = 40 + -10t

T = 4seconds

Time taken back to ground is

T = 4 +4 = 8seconds

HOPE IT WILL HELP YOU