Question

A body is thrown up vertically with a velocity of 50 m/s? (i) What will be it’s velocity at the highest point of its journey? (ii) How high would the body rise? (iii) What time would it take to reach the highest point?

Answer 1

Answer:

i) 0

ii)(50*50)/2*9.8

iii) 50/9.8

Explanation:

by the laws of motion

Answer 2

Answer:1)Zero

2)125m

3)t=5(Approx)

Explanation:

1)The velocity at the top is zero..

2)v^2=u^2+2as

v=0

u=50

s=?

a=-10(gravity)

0=2500+2*-10*s

-2500=-20s

2500/20=125metres

Hope helps

3)v=u+at

v=0

u=50

a=-10(gravity)

t=?

0=50+-10t

-50=-10t

50/10=t

=5sec

Hope Helps

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