Question

a body is thrown up with a speed 29.4ms1. what is a speed after t=1​

Answer 1

Answer:

19.4

Explanation:

by using first equation of motion

Answer 2

Answer:

A body is thrown up with a speed of 29.4m/s.The speed after t=1​swill be $19.6 m/s$

Explanation:

• In the question, it is given that,

       The initial velocity of the body = $29.4m/s$

       The time is taken = $1 s$

• We can solve this problem using the first equation of motion.

        It is given by,

        $V = u+at$    ...(1)

       Where $V$is the final velocity of the body, $u$ is the initial velocity, $a$ is the acceleration due to gravity, and $t$is the time taken by the body.

• Here $a = -g$ , since the body is thrown upwards.

        We know g is the acceleration due to gravity

        $g= 9.8m/s^2$

Substitute these values into equation (1)

$V = 29.4-(9.8\times 1)$

    $=19.6 m/s$