Question

A body is thrown up with a velocity 40ms!
At same time another body is droped from a
height 40 m. Their relative accelaration after
1.3 seconds is
2) g/2 3) 2g
4) zero
1) 4g
pls give clear answer ​

Answer 1

Hey!

Here, u = 40m/s

V = 0 ( highest point)

A = g = -10m/s2

T = ?

By using,

V = u + at

0 = 40 + -10t

T = 4seconds

Time taken back to ground is

T = 4 +4 = 8 seconds

Hope it will help ya

Answer 2

Explanation:

A body is thrown up with a velocity 40 m/s.At same time another body is dropped from a height 40m. Their relative acceleration after 1.3 seconds is. ... So their relative acceleration is always zero .

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