Question

a body is thrown up with a velocity 50m/s. calculate the maximum height reached and the time taken to reach the maximum height (a=10m/s)

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Answer 1

Answer:

Solution:

u=0m/s

v= 50m/s

a=10m/s

t=?

s=?

so, t is:

v=u+at

50=0+10xt

50-0=10t

50=10t

50/10=t

t=5s

Now s:

s=ut+1/2 at2

s= 0x5+1/2 x 10x5x5

s= 0+1/2x50x5

s= 1/2x 250

s= 125m

Hope my answer helps!