Math, asked by sg2007, 2 days ago

A body is thrown up with a velocity of 20m/s and acceleration is 10m/s^2 . find the maximum height and the time ot takes to reach maximum height..

please answer this question..it's urgent..right answer will be marked as the brainliest..no spam comments.

sorry it's physics not maths.​

Answers

Answered by iamasquidkid
2

Answer:

v= u+at

20= 0+10t

t=2s

h= vt

40m.

Answered by rudranarayandubey123
1

Answer:

Step-by-step explanation:

u=20m/s

v=0m/s

a= (-10)m/s^2

2as=v^2-u^2

2(-10)s=(0^2)-(20^2)

-20s= -(40)

s= (-40)/(-20)

 = 2m

v=u+at

0=20+(-10)t

(-20)=(-10)t

t= (-20)/(-10)

t= 2s

SO MAXIMUM HEIGHT REACHED IS 2m IN 2s.

HOPE IT HELPS SOMEONE HERE!!!!!!!!!

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