A body is thrown up with a velocity of 20m/s and acceleration is 10m/s^2 . find the maximum height and the time ot takes to reach maximum height..
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sorry it's physics not maths.
Answers
Answered by
2
Answer:
v= u+at
20= 0+10t
t=2s
h= vt
40m.
Answered by
1
Answer:
Step-by-step explanation:
u=20m/s
v=0m/s
a= (-10)m/s^2
2as=v^2-u^2
2(-10)s=(0^2)-(20^2)
-20s= -(40)
s= (-40)/(-20)
= 2m
v=u+at
0=20+(-10)t
(-20)=(-10)t
t= (-20)/(-10)
t= 2s
SO MAXIMUM HEIGHT REACHED IS 2m IN 2s.
HOPE IT HELPS SOMEONE HERE!!!!!!!!!
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