Question

A body is thrown up with a velocity of 20ms^(-1) .It is uniformly retarded at the rate of 10ms^(-2) .How high would it reach in 2 s?​

Answer 1

Answer:

according to my calculation the answer is 40

Answer 2

$\huge\mathtt\pink{A}\mathtt\red{N}\mathtt\blue{S}\mathtt\green{W}\mathtt\purple{E}\mathtt\green{R} \: 20M$

Given:-

1. initial velocity= 20m/sec
2. Retardation=10m/sec²

To find:-

Highest Distance travelled by it

Solution:-

Use 3rd equation of motion.

$\huge {v}^{2} - {u}^{2} = 2as$

Put value in formula

$\large{0}^{2} - {20}^{2} = 2( - 10)s$

From here Value of S comes

$s = 20m$

SYMBOLS:-

1. S= DISTANCE
2. V =FINAL VELOCITY
3. U=INITIAL VELOCITY
4. A=ACCELERATION