Question

A body is thrown up with a velocity of 29.4m/sec. Find the time taken by the body to reach its highest point? After how much time the body will come back on the ground?

Answer 1

is this like that ? sorry .happy new year in advance

Answer 2

The body will come back on the ground is 3 sec.

What is  projectile motion?

• Projectile motion is the motion of an object projected vertically upward into the air and moving under the influence of gravity.
• Projectile motion is the motion of an object projected horizontally into the air and moving independently of gravity.

According to the question:

$\mathrm{S}=\left(\mathrm{v}^{\wedge} 2-\mathrm{u}^{\wedge} 2\right) / 2 \mathrm{a} \mathrm{s}=\left\{\mathrm{O}^{\wedge} 2-(29.4)^{\wedge} 2\right\} / 2^{*}(-9.8) \\ \\\mathrm{s}=44.1 \\ \\\mathrm{l}) 44.1 \mathrm{~m}(\mathrm{ans}) \mathrm{v}=\mathrm{u}+\mathrm{at} \\\\\\ \mathrm{t}=(\mathrm{v}-\mathrm{u}) / \mathrm{a} \\\\ \mathrm{t}=-29.4 /-9.8 \\ \\\mathrm{t}=3$

Hence,The time it takes for the body to return to the ground is 3 seconds.

Learn more about projectile motion here,

https://brainly.in/question/208506?msp_poc_exp=5

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