Math, asked by gunal171, 1 year ago

A body is thrown up with a velocity of 78.4 m/s. find how high it will rise and how much time it will take to return to its point of projection.

Answers

Answered by varsha33
73
u=78.4m/s
time of ascent=u/g
t=78.4/9.8
t=8sec
time of descent = time of ascent
total time = 2×time of ascent
total time = 2×8=16sec
H=u²/2g
H= (78.4)²/(2×9.8)
H=313.6m
Answered by tejaswijain
1

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