Question

A body is thrown up with a velocity u it reaches maximum height h if its velocity projection is doubled then maximum height it reaches is

Answer 1

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Answer 2

Given:

initial velocity = u

maximum height = h

To Find:

height if velocity is doubled

Solution:

initail velocity = u

maximum height = h

final velocity = v

we know,

v² - u² = 2as

s = v² - u² / 2a

h = -u² / - 2g    {  v = 0 (as it reaches maximum height ) }

h = u² / 2g

Now,

If velocity is doubled

i.e u = 2u

u² = (2u)² = 4u²

h = 4u² / 2g

h = 4 h

So, The maximum height is 4 times the initial height.