Question

a body is thrown up with an initial velocity u and cover maximum height h then h is equal to

Answer 1

Here, initial velocity = u
          final velocity = 0 (at max. height, velocity is 0)
          height covered = h 
          acceleration due to gravity = g 
Using the law of kinematics : v² - u² = 2as
we get -u² = -2gh (considering upward direction as positive, "g" is always                                              downward) 
Thus, we get h = u²/2g

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Answer 2

Initial velocity=u

Final velocity=v=0

Maximum height=h=distance (s)

Now,

v²-u²=2gs

0-u²=2gs

-u²/2g=s.

(Value of g is always taken negative)

So, u²/2g=s

Answer is u²/2g

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