A body is thrown Up with an initial velocity “u" and covers a maximum height of “h", then "h" is equal to?
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Here is the answer..
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Answered by
7
Initial velocity=u
Final velocity=v=0
Maximum height=h=distance (s)
Now,
v²-u²=2gs
0-u²=2gs
-u²/2g=s.
(Value of g is always taken negative)
So, u²/2g=s
Answer is u²/2g
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