Physics, asked by Saluma, 1 year ago

A body is thrown Up with an initial velocity “u" and covers a maximum  height of “h", then "h" is equal to?

Answers

Answered by sarthakkhurana8
5
Here is the answer..
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Answered by rekharr1424
7

Initial velocity=u


Final velocity=v=0


Maximum height=h=distance (s)


Now,


v²-u²=2gs


0-u²=2gs


-u²/2g=s.


(Value of g is always taken negative)


So, u²/2g=s


Answer is u²/2g




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