Question

a body is thrown upvertically with velocity u, the gratest height h, to which it will rise is

Answer 1

Answer:

H = u²/2g

hence, maximum height attained by body u²/2g

Explanation:

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Answer 2

Answer:

u/g

Explanation:

let u be the initial velocity of the particle. At highest point v become zero. now use first equation of motion v = u + at

0 = u -g× tr (tr = time of rise)

tr = u/g