A body is thrown upward and is caught after 4 seconds by thrower. What was initial velocity of the body?
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Answer:
initial velocity u = 19.6m/s2
Explanation:
time taken by a body is thrown upward and return to its initial point of projection is called time of flight
time of flight t = 2u/g
time of flight = t =4s
initial velocity = u = ?
acceleration due to gravity g = 9.8 m/s2
then initial velocity = u= tg/2
u = (4×9.8)/2 = 2× 9.8 = 19.6 m/s2
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