Question

A body is thrown upwards and reaches half of its maximum height. At that position-
(a) its acceleration is minimum
(b) its velocity is maximum
(c) its velocity is zero
(d) its acceleration is constant​

Answer 1

A body is thrown upwards and reaches half of its maximum height

The height reached can be calculated by using the formula:

$h=ut+\frac{1at^{2} }{2}$

During the whole journey, the acceleration of the body would be the same as the acceleration due to gravity.

The acceleration of the body =$9.8m/s^{2}$

The velocity of the body would be zero at the maximum height.

Hence, the correct option is (d) its acceleration is constant​.

Answer 2

A body is thrown upwards and reaches half of its maximum height. At that position   its acceleration is constant​

When a body is thrown upward if air resistance is neglected then body is constantly under gravitational force.

Acceleration due to gravity is constant

Velocity is zero at the highest point.

At position half of its maximum height Potential energy = kinetic energy

Potential Energy = mass x acceleration due to gravity x height

Kinetic Energy   = (1/2) x mass x (velocity)²

Velocity is maximum just before hitting the ground

From the given options correct option is (d) its acceleration is constant​