Question

A body is thrown upwards from ground covers equal distances in 4th and 7th second . with what initial velocity the body was projected

Answer 1

Distance covered by a body in nth second is

x(n)=un-1/2gn^2

Distance covered by a body in (n-1)th second is

x(n-1)=u(n-1) — 1/2g(n-1)^2

Subtract x(n-1) from x(n)

Now plug the values for 4th and 7th second and equate them. You will get your initial velocity(u).

Answer 2

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Explanation:

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