Question

A body is thrown upwards with a velocity of 19.6 m/s. Find the height the body will reach

Answer 1

Maximum height is given by :- 

Hmax =vi^2/2g

Hmax = 19.6^2/2×10

Hmax =384.16/20

Hmax=19.2 m 

Answer 2

$\huge\blue{As-Salamu-Alykum}$


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Maximum height is given by :-

Hmax =vi^2/2g

Hmax = 19.6^2/2×10

Hmax =384.16/20

Hmax=19.2 m

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$\huge\red{INSHALLAH it will help U}$