Question

a body is thrown vertically down from a tower. what is the distance travelled by the body in third second of the initial velocity is 5.5m/sec
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Answer 1

Answer:

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Answer 2

The distance traveled by the body in the third second is 30.5m.

Given:-

The initial velocity of the body = 5.5m/sec

Time = 3rd second

To Find:-

The distance traveled by the body in the third second.

Solution:-

We can simply calculate the distance traveled by the body in a third second by following these simple steps.

As

The initial velocity of the body (u) = 5.5m/sec

Time (n) = 3rd second

Distance traveled (s) =?

a = 10m/s² (acceleration due to gravity)

According to the formula for distance traveled in nth second,

$s = u + \frac{a}{2} (2n - 1)$

on putting the values we get,

$s = 5.5 + \frac{10}{2} (2 \times 3 - 1)$

$s = 5.5 + 5(6 - 1)$

$s = 5.5 + 5 \times 5$

$s = 5.5 + 25$

$s = 30.5m$

Hence, The distance traveled by the body in the third second is 30.5m.

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