A body is thrown vertically downward from a certain height at 30 metre. If acceleration of the body is 10 m/s2, the calculate the velocity with which object will strike the ground?
Answers
Answer :-
The body will strike the ground with a velocity of 24.5 m/s .
Explanation :-
We have :-
→ Height (h) = 30 m
→ Gravitational Acceleration (g) = 10 m/s²
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In this case :
• Initial velocity (u) of the body will be 0 m/s as it is thrown vertically downwards from a height .
• Acceleration (g) will be +ve, as the body is moving in the direction of gravity.
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Now, we can use the 3rd equation of free-fall to calculate the required speed .
v² - u² = 2gh
⇒ v² - 0 = 2(10)(30)
⇒ v² = 600
⇒ v = √600
⇒ v = 24.49 ≈ 24.5 m/s
Given : A body is thrown vertically downward from a certain height at 30 metre. If acceleration of the body is 10 m/s2, the calculate the velocity with which object will strike the ground ?
★ Cᴏɴᴄᴇᴘᴛ :
Here we are provided with the height and acceleration due to gravity which is 30 metre and 10 m/s² respectively. Here we need to find the Final Velocity (v) when it strikes the ground. As final velocity is given there must be initial velocity (u) which must be 0 m/s as it thrown vertically upwards.
★ Sᴏʟᴜᴛɪᴏɴ :
Using the third equation of motion for getting the final velocity of the body. We aren't using the second or third equation because all the conditions favour the third eq. The other two equations won't give out the required result.
✪ v² = u² + 2gh ✪
Here,
- v represents final velocity
- u represents uniform velocity
- g represents acceleration due to gravity
- h represents height
➬ v² = (0)² + 2 × 10 × 30
➬ v² = 0 + 20(30)
➬ v² = 0 + 600
Taking root on both sides
➬ √v² = √600
➬ v = 24.49
✬ Hence, the velocity after striking the ground is 24.49 m/s