Question

A body is thrown vertically downward with a velocity of 5 m/s from a tower of height of h metres. It strikes the ground after 4 seconds. Find h (g = 10 ms–2).

Answer 1

Height of the tower = 80 metres

Explanation:

Given initial velocity = 2 and final velocity = 5 ms-1

acceleration = g = 10 ms-2

Time = 4 s

s = ut + 1/2gt^2

= 0 + 1/2*10*4*4

= 80 m

Height of the tower = 80 metres

Answer 2

Answer:

answer is 100m

Explanation:

u=5m/s

h=?

t=4sec

H=ut+½gt²

=5×4+½×10×4²

=20+80

=100 m

Final Answer=100m