Question

A body is thrown vertically downward with a velocity of 5 m/s from a tower of height of h metres. It strikes the ground after 4 seconds. Find h (g = 10 ms⁻²).

Answer 1

Answer: first find u, with equation v = u +at

Then,after finding u ,use it in the equation H = u^2/2g

Explanation: Here v , is final velocity

U,initial velocity,

H is height ,

A is gravitational constant or G

T is time,

Hope its clear!