Question

A body is thrown vertically up from the top of the building with a velocity of 10m/s . It reaches ground after 5 seconds. Find the height of the building and the velocity with which it reaches the ground ,where g=10m/second square

Answer 1

Answer:

Explanation:U=0(bcz it start from rest)

V=10m/s nd Time=5sec

V=U+at.

10=0+A5

A=10/5=2m/s^2

S=ut+1/2at^2

S=0+1/2×2×(5)^2

S=25 m

Hence...= Height is 25 m