Question

a body is thrown vertically up with a velocity 98m/s. how high will it rise ? ( g = 9.8m/s^2)​

Answer 1

Explanation:

its your answer hope it is helpful

Answer 2

i am using stone as the body

so, please mark me as brainliest

Final Velocity of stone,v=0 because after attaining the maximum height it will come at rest and begin to fall down.

Initial velocity,u=98m/s

Acceleration due to gravity,a= -9.8 m/s because the motion of ball is opposite to the direction of the acceleration caused due to gravity.

∴ Using first kinematical equation, we get

v = u + at

0=98+(-9.8)t

-98= -9.8t

∴ t = -98/-9.8

∴ t=10 seconds

By using second kinematical equation, we get

s = ut + 1/2 at^2

∴ s = 98*10 + 1/2 *(-9.8)*10*10

∴ s = 980 + 1/2 * (-980)

∴ s = 980 + (-490)

∴ s = 490 m

Hope it helps